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4.9x^2-2.25x-3.4=0
a = 4.9; b = -2.25; c = -3.4;
Δ = b2-4ac
Δ = -2.252-4·4.9·(-3.4)
Δ = 71.7025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2.25)-\sqrt{71.7025}}{2*4.9}=\frac{2.25-\sqrt{71.7025}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2.25)+\sqrt{71.7025}}{2*4.9}=\frac{2.25+\sqrt{71.7025}}{9.8} $
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